Simple alternating current (A.C.) circuits
Most present day household and industrial power distribution systems operate with alternating current. Any appliance plugged into a wall outlet uses a.c. and even many battery powered devices such as radio receivers, cordless phones make use of d.c. power supplies derived from a.c. mains source; circuit in modern communication equipment also makes extensive use of a.c.
(A)Graphical representation
Graphical illustration of an a.c. circuit
Source: www.commons.wikimedia.org
(B)Peak and root mean square value of a.c.
The r.m.s value of an alternating current is defined as that value of steady current which would dissipate heat at the same
rate in a given resistance.
Ir.m.s = Ip / √2
=0.7071p
Sine representation of a.c. current/voltage.
Source: www.commons.wikimedia.org
Note: the average of any sinusoidal current alternating over any number of cycles is zero and half average value is given as Iav = 0.637 Ip
(C) Alternating currents in resistors, inductors and capacitors (R.L.C)
Variation of current and voltage in a resistor
Source: www.electronics.tutorials.ws
Circuit elements with alternating current
Circuit element | Amplitude relation | Circuit Quantity | Phase of V |
Resistor | VR = IR | R | In phase with i |
Inductor | VL = IXL | XL = wL | Leads i by 90° |
Capacitor | Vc = IXc | Xc = 1/wC | Lags i by 90° |
(D)The L.R.,R.C.and L.R.C. series circuit
The overall opposition to the flow of current in the a.c. a circuit by any two or all of the three circuit elements (R, L and C) is called impedance and is usually represented by Z while R stands for resistor, L stands for inductor and C stands for capacitor.
ZRL = √X2L + R2
The phase angle between voltage and current is given as:
¢RL = tan-1 (XL / R)
L.R circuit with switch
Source: www.commons.wikimedia.com
R.C series circuit
Source: www.commons.wikimedia.org
L.C series circuit
Source: www.commons.wikimedia.org
(E)Vector diagram of series RLC. circuit
RLC circuit
Source: www.commons.wikimedia.org
ZRLC = √(XL – XC)2 + R2
(F) Resonance and power in RLC circuit
Graph of current versus frequency
Source: www.researchgate.net
(G)power in a.c circuit
Power absorbed in any a.c circuit is given by the equation P=iV
It average power Pav = VpIp cos ¢
Past questions
1.Which of the following conditions occur at resonance in a series RLC circuit? (Wassce 2014)
I.Impedance equals resistance
II.Current is maximum
III.Reactances are maximum
IV. Current and voltage are 90° out of phase.
A. I and II
B. I and III only
C. I, II and III only
D. I,II, III and IV
Answer: A
2. A coil of inductance 0.12H and resistance 4 ohms, is connected across a 240V, 50Hz supply. Calculate the current through it. [π=3.14]. (Wassce 2013)
A. 6.3A
B. 33.3A
C. 37.2A
D. 40.0A
Answer: A
Solution: XL =wL =2πFL =2×3.14×50×0.12= 37.68
VL / XL = 240/37.68 =6.3A
3.An inductor is connected to a 24V, 50Hz mains supply. If the current through the inductor is 1.5A, calculate the inductance of the inductor. (π=22/7). (Wassce 2012)
A. 8.0×102H
B. 7.5×100H
C. 1.6×100H
D. 5.1×10-2H
Answer: D
Solution: XL = v/I = 2πFL
F=50Hz, I=1.5A, V=24
L=V/2πFl = 24/2×22/7×50×1.5
=5.1×10-2H
4.the unit of capacitance is? (Wassce 2011)
A. Farad
B. Coulomb
C. Henry
D. Ohm
Answer: A
5.
In the series a.c circuit shown above, the p.d across the inductor is 8Vr.m.s and that across the resistor is 6 Vr.m.s. The effective voltage is? (Jamb 2016)
A. 10V
B. 2V
C. 14V
D. 48V
Answer: A
Solution: VT = √82 + 62= 10V
6.
The net capacitance in the circuit shown above is? (Jamb 2017)
A. 8.0uF
B. 6.0uF
C. 2.0uF
D. 4.0uF
Answer: C
Solution: CT = 4×(2+2)/4+2+2 = 16/8 =2uF
7.capacitors are used in the induction coil to? (Jamb 2013)
A. Control circuit
B. Dissipate energy
C. Prevent Electric Sparks
D. Prevent distortion of Electric fields
Answer: C
8.In an a.c circuit, the ratio of r.m.s value to peak value of current is? (Jamb 2012)
A. 1/√2
B. √2
C. 2
D. ½
Answer: A
Harry
•2 years ago
Pls can I get more of the Questions